Advanced Types

The definition of $type in the 'Basic Types' section is only a simplified version. The Hoon type system is simple, but not that simple.

The good news is that you can skip this section, at least when you're first learning Hoon. Polymorphism and aliasing are mainly for advanced programmers writing complex infrastructure and/or large functions. Don't worry about them for a little while.

The Full Version of $type

+$  type  $~  %noun
          $@  $?  %noun
                  %void
              ==
          $%  [%atom p=term q=(unit @)]
              [%cell p=type q=type]
              [%core p=type q=coil]
              [%face p=$@(term tune) q=type]
              [%fork p=(set type)]
              [%hint p=(pair type note) q=type]
              [%hold p=type q=hoon]
          ==
::
+$  coil  $:  p=garb                                    ::  name, wet=dry, vary
              q=type                                    ::  context
              r=(pair seminoun (map term tome))         ::  chapters
          ==                                            ::
::
+$  garb  (trel (unit term) poly vair)                  ::  core
+$  poly  ?(%wet %dry)
+$  vair  ?(%gold %iron %lead %zinc)
+$  tome  (pair what (map term hoon))
+$  tune                                                ::  complex
          $~  [~ ~]                                     ::
          $:  p=(map term (unit hoon))                  ::  aliases
              q=(list hoon)                             ::  bridges
          ==                                            ::

If you compare this to the basic $type, you'll see that we've changed two parts: %core and %face. We added polymorphism to %core, and aliases and bridges to %face.

(We also added %hint for hint expressions.)

%core: advanced polymorphism

If cores never changed, we wouldn't need polymorphism. Of course, nouns are immutable and never change, but we use them as templates to construct new nouns around.

Suppose we take a core, a cell [battery payload], and replace the payload with a different noun. Then, we invoke an arm from the battery.

Is this legal? Does it make sense? Every function call in Hoon does this, so we'd better make it work well.

The full core stores both payload types. The type that describes the payload currently in the core is p. The type that describes the payload the core was compiled with is q.q.

In the Bertrand Meyer tradition of type theory, there are two forms of polymorphism: variance and genericity. In Hoon this choice is per core, hence the $poly label in p.q: it can be either %wet or %dry. Dry polymorphism relies on variance; wet polymorphism relies on genericity.

Dry arms

For a dry arm, we apply the Liskov substitution principle: we ask, "can we use any p as if it was a q.q?" This is the same test as in ^- ("kethep") or any type comparison (nest). Intuitively, we ask: "is the new payload compatible with the old payload?"

For a core a, if p.a fits in q.q.a, we can use arms on the core. The product of a dry arm whose expression is b is always defined as [%hold a(p q.q.a, r.p.q %gold) b].

In other words, the subject of the arm computation is the original core type. The type of the modified payload, p, is thrown away. This is of course the normal behavior of a function call in most languages.

Dry polymorphism and core nesting rules

Dry polymorphism works by substituting cores. Typically, the the programmer uses one core as an interface definition, then replaces it with another core which does something useful.

For core b to nest within core a, the batteries of a and b must have the same tree shape, and the product of each b arm must nest within the product of the a arm. Wet arms (see below) are not compatible unless the hoon is exactly the same.

But we also apply a payload test that depends on the rules of variance. Again, this is traditional Meyer type theory; don't worry if you don't know it. These rules should make sense if you just think about them intuitively.

Each core has a "metal" r.p.q which defines its variance model. A core can be invariant (%gold), bivariant (%lead), covariant (%zinc), or contravariant (%iron). The default is gold; a gold core can be cast or converted to any metal, and any metal can be cast or converted to lead.

A gold core a has a read-write payload; another core b that nests within it (i.e., can be substituted for it) must be a gold core whose payload is mutually compatible (+3.a nests in +3.b, +3.b nests in +3.a). Hence, invariant.

A lead core a has an opaque payload. There is no constraint on the payload of a core b which nests within it. Hence, bivariant.

(Opaque here means that the faces and arms are not exported into the namespace, and that the values of faces and arms can't be written to. The object in question can be replaced by something else without breaking type safety.)

An iron core a has a write-only sample (payload head, +6.a) and an opaque context (payload tail, +7.a). A core b which nests within it must be a gold or iron core, such that +6.a nests within +6.b. Hence, contravariant.

A zinc core a has a read-only sample (payload head, +6.a) and an opaque context (payload tail, +7.a). A core b which nests within it must be a gold or zinc core, such that +6.b nests within +6.a. Hence, covariant.

Wet arms

For a wet arm, we ask: "suppose this core was actually compiled using p instead of q.q?" Would the Nock formula we generated for q.q actually work for a p payload?

A wet arm with hoon b in core a produces the type [%hold a b]. Assuming a has a modified payload, this will (lazily) analyze the arm with the caller's modified payload, p.

But of course, we don't actually recompile the arm at runtime. We actually run the formula generated for the original payload, q.q.

When we call a wet arm, we're essentially using the hoon as a macro. We are not generating new code for every call site; we are creating a new type analysis path, which works as if we expanded the callee with the caller's context.

Consider a function like +turn (Haskell +map) which transforms each element of a list. To use +turn, we install a list and a transformation function in a generic core. The type of the list we produce depends on the type of the list and the type of the transformation function. But the Nock formulas for transforming each element of the list will work on any function and any list, so long as the function's argument is the list item.

Again, will this work? A simple (and not quite right) way to ask this question is to compile all the hoons in the battery for both a payload of p and a payload of q.q, and see if they generate exactly the same Nock. The actual algorithm is a little more interesting, but not much.

A Haskeller might say that in a sense, q.q and q.r.q (the original payload and the battery) define a sort of implicit typeclass. And indeed, Hoon uses wet arms for the same kinds of problems as Haskell typeclasses.

Like typeclasses, wet arms / gates are a powerful tool. Don't use them unless you know what you're doing.

Constant folding

There's only one field of the $coil we haven't explained yet: p.r.q. This is simply the compiled battery, if available. (Of course, we compile the hoons in a core against the core itself, and the formulas can't be available while we're compiling them.) External users of the core want this battery constant, though: it lets us fold constants by executing arms at compile time.

%face: aliases and bridges

In the advanced $tune form, the %face type also has a couple of secret superpowers for hacking the namespace. Remember that Hoon doesn't have anything like a symbol table; to resolve a limb, we just search the type depth-first.

If a name is in the p.p +map, it's an alias. (An alias is defined using the =* rune.) The map contains a (unit hoon); if the unit is full, the name resolves to that hoon (compiled against the .q type). If the unit is empty, the name is blocked / skipped (see limb for what this means).

If a name is the q.p $term, it's a bridge. (A bridge is defined using the =, rune.) When we search for a name, we also compile the bridge, and check if the name resolves against the bridge product. If so, we use it.

These hacks let us deal with interesting large-scale problems, like complex library dependencies. You definitely don't need to understand them to just write simple Hoon programs.